Her name is Polina (Полина), I don't think she is a porn star or even a model, really.
She has a page on the Russian social media site fotostrana.ru, I will link to her profile and her gallery, where you can find a number of photos and also one where she wears the same outfit.
Profile:
https://fotostrana.ru/user/79260137/#
Gallery:
https://fotostrana.ru/user/79260137/album/109567681/photos/2385618591/#!
None of the photos in her gallery are available anywhere else on the web, which is a very strong indicator that this is really her profile.
She has a page on the Russian social media site fotostrana.ru, I will link to her profile and her gallery, where you can find a number of photos and also one where she wears the same outfit.
Profile:
https://fotostrana.ru/user/79260137/#
Gallery:
https://fotostrana.ru/user/79260137/album/109567681/photos/2385618591/#!
None of the photos in her gallery are available anywhere else on the web, which is a very strong indicator that this is really her profile.
JonnyGroove confirms this as correct.
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Her name is Polina (Полина), I don't think she is a porn star or even a model, really.
She has a page on the Russian social media site fotostrana.ru, I will link to her profile and her gallery, where you can find a number of photos and also one where she wears the same outfit.
Profile:
https://fotostrana.ru/user/79260137/#
Gallery:
https://fotostrana.ru/user/79260137/album/109567681/photos/2385618591/#!
None of the photos in her gallery are available anywhere else on the web, which is a very strong indicator that this is really her profile.
She has a page on the Russian social media site fotostrana.ru, I will link to her profile and her gallery, where you can find a number of photos and also one where she wears the same outfit.
Profile:
https://fotostrana.ru/user/79260137/#
Gallery:
https://fotostrana.ru/user/79260137/album/109567681/photos/2385618591/#!
None of the photos in her gallery are available anywhere else on the web, which is a very strong indicator that this is really her profile.
JonnyGroove confirms this as correct.
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